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9x^2-108+36x=0
a = 9; b = 36; c = -108;
Δ = b2-4ac
Δ = 362-4·9·(-108)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-72}{2*9}=\frac{-108}{18} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+72}{2*9}=\frac{36}{18} =2 $
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