9x2-115x+300=0

Solution for 9x2-115x+300=0 equation:

9x^2-115x+300=0

a = 9; b = -115; c = +300;
Δ = b2-4ac
Δ = -1152-4·9·300
Δ = 2425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2425}=\sqrt{25*97}=\sqrt{25}*\sqrt{97}=5\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-115)-5\sqrt{97}}{2*9}=\frac{115-5\sqrt{97}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-115)+5\sqrt{97}}{2*9}=\frac{115+5\sqrt{97}}{18}
$