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9x^2-12x+4=36
We move all terms to the left:
9x^2-12x+4-(36)=0
We add all the numbers together, and all the variables
9x^2-12x-32=0
a = 9; b = -12; c = -32;
Δ = b2-4ac
Δ = -122-4·9·(-32)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-36}{2*9}=\frac{-24}{18} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+36}{2*9}=\frac{48}{18} =2+2/3 $
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