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9x^2-14=2x
We move all terms to the left:
9x^2-14-(2x)=0
a = 9; b = -2; c = -14;
Δ = b2-4ac
Δ = -22-4·9·(-14)
Δ = 508
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{508}=\sqrt{4*127}=\sqrt{4}*\sqrt{127}=2\sqrt{127}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{127}}{2*9}=\frac{2-2\sqrt{127}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{127}}{2*9}=\frac{2+2\sqrt{127}}{18} $
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