9x2-15x+6=0

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Solution for 9x2-15x+6=0 equation: 



9x^2-15x+6=0

a = 9; b = -15; c = +6;
Δ = b2-4ac
Δ = -152-4·9·6
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-3}{2*9}=\frac{12}{18}
=2/3
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+3}{2*9}=\frac{18}{18}
=1
$

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