9x2-22x+8=0

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Solution for 9x2-22x+8=0 equation:



9x^2-22x+8=0
a = 9; b = -22; c = +8;
Δ = b2-4ac
Δ = -222-4·9·8
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-14}{2*9}=\frac{8}{18} =4/9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+14}{2*9}=\frac{36}{18} =2 $

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