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9x^2-26x-3=
We move all terms to the left:
9x^2-26x-3-()=0
We add all the numbers together, and all the variables
9x^2-26x=0
a = 9; b = -26; c = 0;
Δ = b2-4ac
Δ = -262-4·9·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-26}{2*9}=\frac{0}{18} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+26}{2*9}=\frac{52}{18} =2+8/9 $
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