If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x^2-2x-36=0
a = 9; b = -2; c = -36;
Δ = b2-4ac
Δ = -22-4·9·(-36)
Δ = 1300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1300}=\sqrt{100*13}=\sqrt{100}*\sqrt{13}=10\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10\sqrt{13}}{2*9}=\frac{2-10\sqrt{13}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10\sqrt{13}}{2*9}=\frac{2+10\sqrt{13}}{18} $
| 11/2x=12 | | (5x-27)(4x)=360 | | 4.8+10m=8.76 | | 3=y/12 | | 10-2.5(x-4)=50 | | A=+55b | | 3/4y-1/2y-5=7 | | 5x−2(x+1)=14 | | (2/3x)(90)=360 | | 10z-30-4z=6(z-5)C | | 3(x+2)-2x=10-4x | | 3(2x+3)=(3√)(x+4) | | N/3+n/6=7/2 | | 3(3m-2=2(3m+3) | | 10-25(x-4)=50 | | 3+2w8=60 | | 4x/(x^2+1)^2=0 | | 45-(x+9)=9x-4 | | 6.4u−5.1u=−3.25 | | c/5=26-2c | | 4^x3.2^(x+2)+2^5=0 | | 2(9-3a)=4a-4(a+3) | | 2x-5x=7 | | 12−4x=−8x | | C=$.18t+$.10 | | 3r-10=10r+4 | | -1/3=5x+10 | | x-2=20-5x | | -4(x+2)+7=5-(x-8) | | 4+2p=10(3/5p-2 | | -3a^2-2a+1=0 | | 12-1/5r=2r |