9x2-424x+3600=0

Solution for 9x2-424x+3600=0 equation:

9x^2-424x+3600=0

a = 9; b = -424; c = +3600;
Δ = b2-4ac
Δ = -4242-4·9·3600
Δ = 50176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50176}=224$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-424)-224}{2*9}=\frac{200}{18}
=11+1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-424)+224}{2*9}=\frac{648}{18}
=36
$