9x2-6x-63=0

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Solution for 9x2-6x-63=0 equation:



9x^2-6x-63=0
a = 9; b = -6; c = -63;
Δ = b2-4ac
Δ = -62-4·9·(-63)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-48}{2*9}=\frac{-42}{18} =-2+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+48}{2*9}=\frac{54}{18} =3 $

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