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9x^2-x-8=0
We add all the numbers together, and all the variables
9x^2-1x-8=0
a = 9; b = -1; c = -8;
Δ = b2-4ac
Δ = -12-4·9·(-8)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-17}{2*9}=\frac{-16}{18} =-8/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+17}{2*9}=\frac{18}{18} =1 $
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