9x2=-33*3x

Solution for 9x2=-33*3x equation:

9x^2=-33*3x

We move all terms to the left:

9x^2-(-33*3x)=0

We get rid of parentheses

9x^2+33*3x=0

Wy multiply elements

9x^2+99x=0

a = 9; b = 99; c = 0;
Δ = b2-4ac
Δ = 992-4·9·0
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9801}=99$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-99}{2*9}=\frac{-198}{18}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+99}{2*9}=\frac{0}{18}
=0
$