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9x^2=1296
We move all terms to the left:
9x^2-(1296)=0
a = 9; b = 0; c = -1296;
Δ = b2-4ac
Δ = 02-4·9·(-1296)
Δ = 46656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{46656}=216$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-216}{2*9}=\frac{-216}{18} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+216}{2*9}=\frac{216}{18} =12 $
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