If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x^2=49.
We move all terms to the left:
9x^2-(49.)=0
We add all the numbers together, and all the variables
9x^2-49=0
a = 9; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·9·(-49)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42}{2*9}=\frac{-42}{18} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42}{2*9}=\frac{42}{18} =2+1/3 $
| c-(-8)=13 | | 3x+11+x+15=90 | | -2m=-7 | | 15-x=27-3 | | 3/4x–4=–19 | | (13x+5)+(110)=180 | | n^2=5n-3 | | 10=z* | | u+1.81=4.43 | | x-53=45 | | 2(x+4)–x–6= | | (-7/2z+4)+(1/5z=15)= | | 2(x+4)–x–6=4 | | 16x+1=12x+13 | | (7x+15)=(10x-33) | | (3x+29)+(16x+23)=90 | | -13+34p=-116 | | 3/2x+3/2=9/2 | | (-7/2=z+4)+(1/5z-15)= | | -4(4k-8)=-32+4k | | x+29=5x+49 | | (3x+16)=(5x-10) | | 17/x=1/2 | | F(x)=(2x^2-10x-10)(x) | | 7x+28=4x+40 | | 2x+4-8x+5=-9 | | 2+5/7x=7 | | (4x-6)+(4x-6)=180 | | X/6+2=6-x/6 | | 7 · u = 79 | | 8/x=3/15 | | 2(3x+2)=2(-3x+2) |