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9x=-6+3(3x+2
We move all terms to the left:
9x-(-6+3(3x+2)=0
We calculate terms in parentheses: -(-6+3(3x+2), so:We add all the numbers together, and all the variables
-6+3(3x+2
determiningTheFunctionDomain 3(3x+2-6
Back to the equation:
-(3(3x+2-6)
9x-(3(3x-4)=0
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| 3(u+5)=8u+30 | | 0.06+0.06x=0.042 | | 5x^2+16=141 | | 2.25x+.50x=44 | | 1/4x-4(2)=-1/2(1/2x+ | | 17w-15w=16 | | 7m+18m=42m+11m | | 6(3x+4)-4=18 | | 7x-13=3x+43 | | 2p^2-108-6p=0 | | 4x-11=5x-10 | | n2+ 7=9 | | t/5+84=94 | | t/5+ 84=94 | | 8x=6x=-18 | | t5+ 84=94 | | x+1.6=0.8x=-1.2 | | x/5=7=16 | | 6x+33+5x-7=180 | | 9v+6=-93 | | 12-7x-10=1-8x+2 | | 8w+42=15w | | 9(8d-5)=12d-2 | | 5x-2+7=180 | | 2r+12=60 | | 9(X+30=4x-3 | | 5x-2+147=180 | | 5=v/2+2 | | 9a–5=3+5a | | 4.3+z=-9 | | 1/4(16x-12)=10 | | n/0.4=0.04/5 |