9y+-4+-6=2(y+1)+-5

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Solution for 9y+-4+-6=2(y+1)+-5 equation: 



9y+-4+-6=2(y+1)+-5

We move all terms to the left:

9y+-4+-6-(2(y+1)+-5)=0

We add all the numbers together, and all the variables

9y-(2(y+1)+-5)=0

We use the square of the difference formula

9y-(2(y+1)-5)=0



We calculate terms in parentheses: -(2(y+1)-5), so:

2(y+1)-5

We multiply parentheses

2y+2-5

We add all the numbers together, and all the variables

2y-3

Back to the equation:

-(2y-3)



We get rid of parentheses

9y-2y+3=0

We add all the numbers together, and all the variables

7y+3=0

We move all terms containing y to the left, all other terms to the right

7y=-3

y=-3/7

y=-3/7

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