9y+27=3(y+1)

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Solution for 9y+27=3(y+1) equation: 



9y+27=3(y+1)

We move all terms to the left:

9y+27-(3(y+1))=0



We calculate terms in parentheses: -(3(y+1)), so:

3(y+1)

We multiply parentheses

3y+3

Back to the equation:

-(3y+3)



We get rid of parentheses

9y-3y-3+27=0

We add all the numbers together, and all the variables

6y+24=0

We move all terms containing y to the left, all other terms to the right

6y=-24

y=-24/6

y=-4

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