9y+3(3y-5)=15

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Solution for 9y+3(3y-5)=15 equation: 



9y+3(3y-5)=15

We move all terms to the left:

9y+3(3y-5)-(15)=0

We multiply parentheses

9y+9y-15-15=0

We add all the numbers together, and all the variables

18y-30=0

We move all terms containing y to the left, all other terms to the right

18y=30

y=30/18

y=1+2/3

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