9y+3(y+4)=3(4+y)

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Solution for 9y+3(y+4)=3(4+y) equation: 



9y+3(y+4)=3(4+y)

We move all terms to the left:

9y+3(y+4)-(3(4+y))=0

We add all the numbers together, and all the variables

9y+3(y+4)-(3(y+4))=0

We multiply parentheses

9y+3y-(3(y+4))+12=0



We calculate terms in parentheses: -(3(y+4)), so:

3(y+4)

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)



We add all the numbers together, and all the variables

12y-(3y+12)+12=0

We get rid of parentheses

12y-3y-12+12=0

We add all the numbers together, and all the variables

9y=0

y=0/9

y=0

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