9y+3(y+4)=3(4+y)

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Solution for 9y+3(y+4)=3(4+y) equation:



9y+3(y+4)=3(4+y)
We move all terms to the left:
9y+3(y+4)-(3(4+y))=0
We add all the numbers together, and all the variables
9y+3(y+4)-(3(y+4))=0
We multiply parentheses
9y+3y-(3(y+4))+12=0
We calculate terms in parentheses: -(3(y+4)), so:
3(y+4)
We multiply parentheses
3y+12
Back to the equation:
-(3y+12)
We add all the numbers together, and all the variables
12y-(3y+12)+12=0
We get rid of parentheses
12y-3y-12+12=0
We add all the numbers together, and all the variables
9y=0
y=0/9
y=0

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