9y+3-3(-3y-1)=3(y-1)

Solution for 9y+3-3(-3y-1)=3(y-1) equation:

9y+3-3(-3y-1)=3(y-1)

We move all terms to the left:

9y+3-3(-3y-1)-(3(y-1))=0

We multiply parentheses

9y+9y-(3(y-1))+3+3=0


We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)


We add all the numbers together, and all the variables

18y-(3y-3)+6=0

We get rid of parentheses

18y-3y+3+6=0

We add all the numbers together, and all the variables

15y+9=0

We move all terms containing y to the left, all other terms to the right

15y=-9

y=-9/15

y=-3/5