9y+3=2(4y-5)

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Solution for 9y+3=2(4y-5) equation: 



9y+3=2(4y-5)

We move all terms to the left:

9y+3-(2(4y-5))=0



We calculate terms in parentheses: -(2(4y-5)), so:

2(4y-5)

We multiply parentheses

8y-10

Back to the equation:

-(8y-10)



We get rid of parentheses

9y-8y+10+3=0

We add all the numbers together, and all the variables

y+13=0

We move all terms containing y to the left, all other terms to the right

y=-13

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