9y+41=5(y+1)

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Solution for 9y+41=5(y+1) equation: 



9y+41=5(y+1)

We move all terms to the left:

9y+41-(5(y+1))=0



We calculate terms in parentheses: -(5(y+1)), so:

5(y+1)

We multiply parentheses

5y+5

Back to the equation:

-(5y+5)



We get rid of parentheses

9y-5y-5+41=0

We add all the numbers together, and all the variables

4y+36=0

We move all terms containing y to the left, all other terms to the right

4y=-36

y=-36/4

y=-9

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