9y-(2y-3)=5(y-2)+1

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Solution for 9y-(2y-3)=5(y-2)+1 equation: 



9y-(2y-3)=5(y-2)+1

We move all terms to the left:

9y-(2y-3)-(5(y-2)+1)=0

We get rid of parentheses

9y-2y-(5(y-2)+1)+3=0



We calculate terms in parentheses: -(5(y-2)+1), so:

5(y-2)+1

We multiply parentheses

5y-10+1

We add all the numbers together, and all the variables

5y-9

Back to the equation:

-(5y-9)



We add all the numbers together, and all the variables

7y-(5y-9)+3=0

We get rid of parentheses

7y-5y+9+3=0

We add all the numbers together, and all the variables

2y+12=0

We move all terms containing y to the left, all other terms to the right

2y=-12

y=-12/2

y=-6

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