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9y-(2y-3)=5(y-2)+3
We move all terms to the left:
9y-(2y-3)-(5(y-2)+3)=0
We get rid of parentheses
9y-2y-(5(y-2)+3)+3=0
We calculate terms in parentheses: -(5(y-2)+3), so:We add all the numbers together, and all the variables
5(y-2)+3
We multiply parentheses
5y-10+3
We add all the numbers together, and all the variables
5y-7
Back to the equation:
-(5y-7)
7y-(5y-7)+3=0
We get rid of parentheses
7y-5y+7+3=0
We add all the numbers together, and all the variables
2y+10=0
We move all terms containing y to the left, all other terms to the right
2y=-10
y=-10/2
y=-5
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