9y-(2y-3)=5(y-2)+y

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Solution for 9y-(2y-3)=5(y-2)+y equation: 



9y-(2y-3)=5(y-2)+y

We move all terms to the left:

9y-(2y-3)-(5(y-2)+y)=0

We get rid of parentheses

9y-2y-(5(y-2)+y)+3=0



We calculate terms in parentheses: -(5(y-2)+y), so:

5(y-2)+y

We add all the numbers together, and all the variables

y+5(y-2)

We multiply parentheses

y+5y-10

We add all the numbers together, and all the variables

6y-10

Back to the equation:

-(6y-10)



We add all the numbers together, and all the variables

7y-(6y-10)+3=0

We get rid of parentheses

7y-6y+10+3=0

We add all the numbers together, and all the variables

y+13=0

We move all terms containing y to the left, all other terms to the right

y=-13

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