9y-2(2y-3)=5(y-2)+2y

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Solution for 9y-2(2y-3)=5(y-2)+2y equation: 



9y-2(2y-3)=5(y-2)+2y

We move all terms to the left:

9y-2(2y-3)-(5(y-2)+2y)=0

We multiply parentheses

9y-4y-(5(y-2)+2y)+6=0



We calculate terms in parentheses: -(5(y-2)+2y), so:

5(y-2)+2y

We add all the numbers together, and all the variables

2y+5(y-2)

We multiply parentheses

2y+5y-10

We add all the numbers together, and all the variables

7y-10

Back to the equation:

-(7y-10)



We add all the numbers together, and all the variables

5y-(7y-10)+6=0

We get rid of parentheses

5y-7y+10+6=0

We add all the numbers together, and all the variables

-2y+16=0

We move all terms containing y to the left, all other terms to the right

-2y=-16

y=-16/-2

y=+8

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