9y-3(y-1)=6+y

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Solution for 9y-3(y-1)=6+y equation: 



9y-3(y-1)=6+y

We move all terms to the left:

9y-3(y-1)-(6+y)=0

We add all the numbers together, and all the variables

9y-3(y-1)-(y+6)=0

We multiply parentheses

9y-3y-(y+6)+3=0

We get rid of parentheses

9y-3y-y-6+3=0

We add all the numbers together, and all the variables

5y-3=0

We move all terms containing y to the left, all other terms to the right

5y=3

y=3/5

y=3/5

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