If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9y-32=5(y-8)
We move all terms to the left:
9y-32-(5(y-8))=0
We calculate terms in parentheses: -(5(y-8)), so:We get rid of parentheses
5(y-8)
We multiply parentheses
5y-40
Back to the equation:
-(5y-40)
9y-5y+40-32=0
We add all the numbers together, and all the variables
4y+8=0
We move all terms containing y to the left, all other terms to the right
4y=-8
y=-8/4
y=-2
| 5/3x+3=8 | | 5x-14=x-34 | | 3(w+4)-7w=8 | | (2.5)^x=49 | | x÷6+28=40 | | 26=3(u-3)+4u | | (2x+5)*2=0 | | x-1/7=3/4 | | 18=8x-22 | | 6x-+4=11 | | (r)/(2)*((3)/(4)-4r)=((r)/(4)-(1)/(2))*((1)/(2)-8r) | | 1^x+2^x+3^x=2 | | 10m=6=96 | | 4y+(100/y)=0 | | 2n^2-7n-130=0 | | 17+3n=20n | | 9x/2+41=x/2+18 | | 12a+9=3(+) | | 110/132=x/132 | | (5x+16)*2=x+5 | | e+8.4=1.2 | | e8.4=1.2 | | 2x^2-5x-27=0 | | (z-5)(z+3)=(z+7)(z+2) | | 2-(3x-4)=0.75+x | | 1/2t=t-5/2 | | 9h+9=90# | | 4y-14=39 | | 12x=1/15 | | -5x+7-7(x-1)=-(4x-4)-7x+7 | | 4x-2(2-3x)=3(x-5)-10 | | 4x-2(2-3x)=(x-5)-10 |