9y-33=3(y+5)

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Solution for 9y-33=3(y+5) equation: 



9y-33=3(y+5)

We move all terms to the left:

9y-33-(3(y+5))=0



We calculate terms in parentheses: -(3(y+5)), so:

3(y+5)

We multiply parentheses

3y+15

Back to the equation:

-(3y+15)



We get rid of parentheses

9y-3y-15-33=0

We add all the numbers together, and all the variables

6y-48=0

We move all terms containing y to the left, all other terms to the right

6y=48

y=48/6

y=8

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