9y-33=3(y-5)

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Solution for 9y-33=3(y-5) equation: 



9y-33=3(y-5)

We move all terms to the left:

9y-33-(3(y-5))=0



We calculate terms in parentheses: -(3(y-5)), so:

3(y-5)

We multiply parentheses

3y-15

Back to the equation:

-(3y-15)



We get rid of parentheses

9y-3y+15-33=0

We add all the numbers together, and all the variables

6y-18=0

We move all terms containing y to the left, all other terms to the right

6y=18

y=18/6

y=3

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