9y-4(y-3)=8-(3y-5)

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Solution for 9y-4(y-3)=8-(3y-5) equation:



9y-4(y-3)=8-(3y-5)
We move all terms to the left:
9y-4(y-3)-(8-(3y-5))=0
We multiply parentheses
9y-4y-(8-(3y-5))+12=0
We calculate terms in parentheses: -(8-(3y-5)), so:
8-(3y-5)
determiningTheFunctionDomain -(3y-5)+8
We get rid of parentheses
-3y+5+8
We add all the numbers together, and all the variables
-3y+13
Back to the equation:
-(-3y+13)
We add all the numbers together, and all the variables
5y-(-3y+13)+12=0
We get rid of parentheses
5y+3y-13+12=0
We add all the numbers together, and all the variables
8y-1=0
We move all terms containing y to the left, all other terms to the right
8y=1
y=1/8
y=1/8

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