9y-5(1+y)=2(2y-2)-15

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Solution for 9y-5(1+y)=2(2y-2)-15 equation:


Simplifying
9y + -5(1 + y) = 2(2y + -2) + -15
9y + (1 * -5 + y * -5) = 2(2y + -2) + -15
9y + (-5 + -5y) = 2(2y + -2) + -15

Reorder the terms:
-5 + 9y + -5y = 2(2y + -2) + -15

Combine like terms: 9y + -5y = 4y
-5 + 4y = 2(2y + -2) + -15

Reorder the terms:
-5 + 4y = 2(-2 + 2y) + -15
-5 + 4y = (-2 * 2 + 2y * 2) + -15
-5 + 4y = (-4 + 4y) + -15

Reorder the terms:
-5 + 4y = -4 + -15 + 4y

Combine like terms: -4 + -15 = -19
-5 + 4y = -19 + 4y

Add '-4y' to each side of the equation.
-5 + 4y + -4y = -19 + 4y + -4y

Combine like terms: 4y + -4y = 0
-5 + 0 = -19 + 4y + -4y
-5 = -19 + 4y + -4y

Combine like terms: 4y + -4y = 0
-5 = -19 + 0
-5 = -19

Solving
-5 = -19

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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