9z+(3z-7)=(2z-6)+23

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Solution for 9z+(3z-7)=(2z-6)+23 equation: 



9z+(3z-7)=(2z-6)+23

We move all terms to the left:

9z+(3z-7)-((2z-6)+23)=0

We get rid of parentheses

9z+3z-((2z-6)+23)-7=0



We calculate terms in parentheses: -((2z-6)+23), so:

(2z-6)+23

We get rid of parentheses

2z-6+23

We add all the numbers together, and all the variables

2z+17

Back to the equation:

-(2z+17)



We add all the numbers together, and all the variables

12z-(2z+17)-7=0

We get rid of parentheses

12z-2z-17-7=0

We add all the numbers together, and all the variables

10z-24=0

We move all terms containing z to the left, all other terms to the right

10z=24

z=24/10

z=2+2/5

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