9z+10=1-(5-3z)

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Solution for 9z+10=1-(5-3z) equation: 



9z+10=1-(5-3z)

We move all terms to the left:

9z+10-(1-(5-3z))=0

We add all the numbers together, and all the variables

9z-(1-(-3z+5))+10=0



We calculate terms in parentheses: -(1-(-3z+5)), so:

1-(-3z+5)

determiningTheFunctionDomain
-(-3z+5)+1

We get rid of parentheses

3z-5+1

We add all the numbers together, and all the variables

3z-4

Back to the equation:

-(3z-4)



We get rid of parentheses

9z-3z+4+10=0

We add all the numbers together, and all the variables

6z+14=0

We move all terms containing z to the left, all other terms to the right

6z=-14

z=-14/6

z=-2+1/3

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