9z+12=6z+48

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Solution for 9z+12=6z+48 equation: 



9z+12=6z+48

We move all terms to the left:

9z+12-(6z+48)=0

We get rid of parentheses

9z-6z-48+12=0

We add all the numbers together, and all the variables

3z-36=0

We move all terms containing z to the left, all other terms to the right

3z=36

z=36/3

z=12

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