9z+12=6z+48

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Solution for 9z+12=6z+48 equation:



9z+12=6z+48
We move all terms to the left:
9z+12-(6z+48)=0
We get rid of parentheses
9z-6z-48+12=0
We add all the numbers together, and all the variables
3z-36=0
We move all terms containing z to the left, all other terms to the right
3z=36
z=36/3
z=12

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