9z+27=3(9z+9)

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Solution for 9z+27=3(9z+9) equation: 



9z+27=3(9z+9)

We move all terms to the left:

9z+27-(3(9z+9))=0



We calculate terms in parentheses: -(3(9z+9)), so:

3(9z+9)

We multiply parentheses

27z+27

Back to the equation:

-(27z+27)



We get rid of parentheses

9z-27z-27+27=0

We add all the numbers together, and all the variables

-18z=0

z=0/-18

z=0

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