9z+27=3(9z+9)

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Solution for 9z+27=3(9z+9) equation:



9z+27=3(9z+9)
We move all terms to the left:
9z+27-(3(9z+9))=0
We calculate terms in parentheses: -(3(9z+9)), so:
3(9z+9)
We multiply parentheses
27z+27
Back to the equation:
-(27z+27)
We get rid of parentheses
9z-27z-27+27=0
We add all the numbers together, and all the variables
-18z=0
z=0/-18
z=0

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