9z-7/3z+5=3z-4/z+6

Solution for 9z-7/3z+5=3z-4/z+6 equation:

9z-7/3z+5=3z-4/z+6

We move all terms to the left:

9z-7/3z+5-(3z-4/z+6)=0


Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R



Domain of the equation: z+6)!=0

z∈R


We get rid of parentheses

9z-7/3z-3z+4/z-6+5=0

We calculate fractions


9z-3z+(-7z)/3z^2+12z/3z^2-6+5=0

We add all the numbers together, and all the variables

6z+(-7z)/3z^2+12z/3z^2-1=0

We multiply all the terms by the denominator


6z*3z^2+(-7z)+12z-1*3z^2=0

We add all the numbers together, and all the variables

12z+6z*3z^2+(-7z)-1*3z^2=0

Wy multiply elements

18z^3-3z^2+12z+(-7z)=0

We get rid of parentheses

18z^3-3z^2+12z-7z=0

We do not support ezpression: z^3