9z=4(z-2)+3

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Solution for 9z=4(z-2)+3 equation: 



9z=4(z-2)+3

We move all terms to the left:

9z-(4(z-2)+3)=0



We calculate terms in parentheses: -(4(z-2)+3), so:

4(z-2)+3

We multiply parentheses

4z-8+3

We add all the numbers together, and all the variables

4z-5

Back to the equation:

-(4z-5)



We get rid of parentheses

9z-4z+5=0

We add all the numbers together, and all the variables

5z+5=0

We move all terms containing z to the left, all other terms to the right

5z=-5

z=-5/5

z=-1

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