9z=6(1/2z-2)

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Solution for 9z=6(1/2z-2) equation: 



9z=6(1/2z-2)

We move all terms to the left:

9z-(6(1/2z-2))=0



Domain of the equation: 2z-2))!=0

z∈R



We multiply all the terms by the denominator


9z*2z-2))-(6(1=0

We add all the numbers together, and all the variables

9z*2z=0

Wy multiply elements

18z^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{36}=0$

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