9z=6(1/2z-2)

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Solution for 9z=6(1/2z-2) equation:



9z=6(1/2z-2)
We move all terms to the left:
9z-(6(1/2z-2))=0
Domain of the equation: 2z-2))!=0
z∈R
We multiply all the terms by the denominator
9z*2z-2))-(6(1=0
We add all the numbers together, and all the variables
9z*2z=0
Wy multiply elements
18z^2=0
a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{36}=0$

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