=(2b+1)(2b-1)

Solution for =(2b+1)(2b-1) equation:

Simplifying
0 = (2b + 1)(2b + -1)

Reorder the terms:
0 = (1 + 2b)(2b + -1)

Reorder the terms:
0 = (1 + 2b)(-1 + 2b)

Multiply (1 + 2b) * (-1 + 2b)
0 = (1(-1 + 2b) + 2b * (-1 + 2b))
0 = ((-1 * 1 + 2b * 1) + 2b * (-1 + 2b))
0 = ((-1 + 2b) + 2b * (-1 + 2b))
0 = (-1 + 2b + (-1 * 2b + 2b * 2b))
0 = (-1 + 2b + (-2b + 4b2))

Combine like terms: 2b + -2b = 0
0 = (-1 + 0 + 4b2)
0 = (-1 + 4b2)

Solving
0 = -1 + 4b2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b2' to each side of the equation.
0 + -4b2 = -1 + 4b2 + -4b2
Remove the zero:
-4b2 = -1 + 4b2 + -4b2

Combine like terms: 4b2 + -4b2 = 0
-4b2 = -1 + 0
-4b2 = -1

Divide each side by '-4'.
b2 = 0.25

Simplifying
b2 = 0.25

Take the square root of each side:
b = {-0.5, 0.5}