=(3c-3)(4c-5)

Solution for =(3c-3)(4c-5) equation:

Simplifying
0 = (3c + -3)(4c + -5)

Reorder the terms:
0 = (-3 + 3c)(4c + -5)

Reorder the terms:
0 = (-3 + 3c)(-5 + 4c)

Multiply (-3 + 3c) * (-5 + 4c)
0 = (-3(-5 + 4c) + 3c * (-5 + 4c))
0 = ((-5 * -3 + 4c * -3) + 3c * (-5 + 4c))
0 = ((15 + -12c) + 3c * (-5 + 4c))
0 = (15 + -12c + (-5 * 3c + 4c * 3c))
0 = (15 + -12c + (-15c + 12c2))

Combine like terms: -12c + -15c = -27c
0 = (15 + -27c + 12c2)

Solving
0 = 15 + -27c + 12c2

Solving for variable 'c'.

Combine like terms: 0 + -15 = -15
-15 + 27c + -12c2 = 15 + -27c + 12c2 + -15 + 27c + -12c2

Reorder the terms:
-15 + 27c + -12c2 = 15 + -15 + -27c + 27c + 12c2 + -12c2

Combine like terms: 15 + -15 = 0
-15 + 27c + -12c2 = 0 + -27c + 27c + 12c2 + -12c2
-15 + 27c + -12c2 = -27c + 27c + 12c2 + -12c2

Combine like terms: -27c + 27c = 0
-15 + 27c + -12c2 = 0 + 12c2 + -12c2
-15 + 27c + -12c2 = 12c2 + -12c2

Combine like terms: 12c2 + -12c2 = 0
-15 + 27c + -12c2 = 0

Factor out the Greatest Common Factor (GCF), '3'.
3(-5 + 9c + -4c2) = 0

Factor a trinomial.
3((-5 + 4c)(1 + -1c)) = 0

Ignore the factor 3.
Subproblem 1
Set the factor '(-5 + 4c)' equal to zero and attempt to solve:

Simplifying
-5 + 4c = 0

Solving
-5 + 4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 4c = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 4c = 0 + 5
4c = 0 + 5

Combine like terms: 0 + 5 = 5
4c = 5

Divide each side by '4'.
c = 1.25

Simplifying
c = 1.25
Subproblem 2
Set the factor '(1 + -1c)' equal to zero and attempt to solve:

Simplifying
1 + -1c = 0

Solving
1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1c = 0 + -1
-1c = 0 + -1

Combine like terms: 0 + -1 = -1
-1c = -1

Divide each side by '-1'.
c = 1

Simplifying
c = 1
Solution
c = {1.25, 1}