=(4c-1)(5c+3)

Solution for =(4c-1)(5c+3) equation:

Simplifying
0 = (4c + -1)(5c + 3)

Reorder the terms:
0 = (-1 + 4c)(5c + 3)

Reorder the terms:
0 = (-1 + 4c)(3 + 5c)

Multiply (-1 + 4c) * (3 + 5c)
0 = (-1(3 + 5c) + 4c * (3 + 5c))
0 = ((3 * -1 + 5c * -1) + 4c * (3 + 5c))
0 = ((-3 + -5c) + 4c * (3 + 5c))
0 = (-3 + -5c + (3 * 4c + 5c * 4c))
0 = (-3 + -5c + (12c + 20c2))

Combine like terms: -5c + 12c = 7c
0 = (-3 + 7c + 20c2)

Solving
0 = -3 + 7c + 20c2

Solving for variable 'c'.

Combine like terms: 0 + 3 = 3
3 + -7c + -20c2 = -3 + 7c + 20c2 + 3 + -7c + -20c2

Reorder the terms:
3 + -7c + -20c2 = -3 + 3 + 7c + -7c + 20c2 + -20c2

Combine like terms: -3 + 3 = 0
3 + -7c + -20c2 = 0 + 7c + -7c + 20c2 + -20c2
3 + -7c + -20c2 = 7c + -7c + 20c2 + -20c2

Combine like terms: 7c + -7c = 0
3 + -7c + -20c2 = 0 + 20c2 + -20c2
3 + -7c + -20c2 = 20c2 + -20c2

Combine like terms: 20c2 + -20c2 = 0
3 + -7c + -20c2 = 0

Factor a trinomial.
(1 + -4c)(3 + 5c) = 0

Subproblem 1
Set the factor '(1 + -4c)' equal to zero and attempt to solve:

Simplifying
1 + -4c = 0

Solving
1 + -4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -4c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4c = 0 + -1
-4c = 0 + -1

Combine like terms: 0 + -1 = -1
-4c = -1

Divide each side by '-4'.
c = 0.25

Simplifying
c = 0.25
Subproblem 2
Set the factor '(3 + 5c)' equal to zero and attempt to solve:

Simplifying
3 + 5c = 0

Solving
3 + 5c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 5c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 5c = 0 + -3
5c = 0 + -3

Combine like terms: 0 + -3 = -3
5c = -3

Divide each side by '5'.
c = -0.6

Simplifying
c = -0.6
Solution
c = {0.25, -0.6}