=(4x+3)(4x-3)

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Solution for =(4x+3)(4x-3) equation:


Simplifying
0 = (4x + 3)(4x + -3)

Reorder the terms:
0 = (3 + 4x)(4x + -3)

Reorder the terms:
0 = (3 + 4x)(-3 + 4x)

Multiply (3 + 4x) * (-3 + 4x)
0 = (3(-3 + 4x) + 4x * (-3 + 4x))
0 = ((-3 * 3 + 4x * 3) + 4x * (-3 + 4x))
0 = ((-9 + 12x) + 4x * (-3 + 4x))
0 = (-9 + 12x + (-3 * 4x + 4x * 4x))
0 = (-9 + 12x + (-12x + 16x2))

Combine like terms: 12x + -12x = 0
0 = (-9 + 0 + 16x2)
0 = (-9 + 16x2)

Solving
0 = -9 + 16x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16x2' to each side of the equation.
0 + -16x2 = -9 + 16x2 + -16x2
Remove the zero:
-16x2 = -9 + 16x2 + -16x2

Combine like terms: 16x2 + -16x2 = 0
-16x2 = -9 + 0
-16x2 = -9

Divide each side by '-16'.
x2 = 0.5625

Simplifying
x2 = 0.5625

Take the square root of each side:
x = {-0.75, 0.75}

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