=(6-3i)(4+2i)

Solution for =(6-3i)(4+2i) equation:

Simplifying
0 = (6 + -3i)(4 + 2i)

Multiply (6 + -3i) * (4 + 2i)
0 = (6(4 + 2i) + -3i * (4 + 2i))
0 = ((4 * 6 + 2i * 6) + -3i * (4 + 2i))
0 = ((24 + 12i) + -3i * (4 + 2i))
0 = (24 + 12i + (4 * -3i + 2i * -3i))
0 = (24 + 12i + (-12i + -6i2))

Combine like terms: 12i + -12i = 0
0 = (24 + 0 + -6i2)
0 = (24 + -6i2)

Solving
0 = 24 + -6i2

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '6i2' to each side of the equation.
0 + 6i2 = 24 + -6i2 + 6i2
Remove the zero:
6i2 = 24 + -6i2 + 6i2

Combine like terms: -6i2 + 6i2 = 0
6i2 = 24 + 0
6i2 = 24

Divide each side by '6'.
i2 = 4

Simplifying
i2 = 4

Take the square root of each side:
i = {-2, 2}