=-(-2x2)+3x-7

Solution for =-(-2x2)+3x-7 equation:

=-(-2x^2)+3x-7

We move all terms to the left:

-(-(-2x^2)+3x-7)=0


We calculate terms in parentheses: -(-(-2x^2)+3x-7), so:

-(-2x^2)+3x-7

We get rid of parentheses

2x^2+3x-7

Back to the equation:

-(2x^2+3x-7)


We get rid of parentheses

-2x^2-3x+7=0

a = -2; b = -3; c = +7;
Δ = b2-4ac
Δ = -32-4·(-2)·7
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{65}}{2*-2}=\frac{3-\sqrt{65}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{65}}{2*-2}=\frac{3+\sqrt{65}}{-4}
$