=-16t2+96t+256

Solution for =-16t2+96t+256 equation:

=-16t^2+96t+256

We move all terms to the left:

-(-16t^2+96t+256)=0

We get rid of parentheses

16t^2-96t-256=0

a = 16; b = -96; c = -256;
Δ = b2-4ac
Δ = -962-4·16·(-256)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-160}{2*16}=\frac{-64}{32}
=-2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+160}{2*16}=\frac{256}{32}
=8
$