=-4.9t2+8.8t+10

Solution for =-4.9t2+8.8t+10 equation:

=-4.9t^2+8.8t+10

We move all terms to the left:

-(-4.9t^2+8.8t+10)=0

We get rid of parentheses

4.9t^2-8.8t-10=0

a = 4.9; b = -8.8; c = -10;
Δ = b2-4ac
Δ = -8.82-4·4.9·(-10)
Δ = 273.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.8)-\sqrt{273.44}}{2*4.9}=\frac{8.8-\sqrt{273.44}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.8)+\sqrt{273.44}}{2*4.9}=\frac{8.8+\sqrt{273.44}}{9.8}
$