=6(8+3c)+4(10+2c)

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Solution for =6(8+3c)+4(10+2c) equation:


Simplifying
0 = 6(8 + 3c) + 4(10 + 2c)
0 = (8 * 6 + 3c * 6) + 4(10 + 2c)
0 = (48 + 18c) + 4(10 + 2c)
0 = 48 + 18c + (10 * 4 + 2c * 4)
0 = 48 + 18c + (40 + 8c)

Reorder the terms:
0 = 48 + 40 + 18c + 8c

Combine like terms: 48 + 40 = 88
0 = 88 + 18c + 8c

Combine like terms: 18c + 8c = 26c
0 = 88 + 26c

Solving
0 = 88 + 26c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-26c' to each side of the equation.
0 + -26c = 88 + 26c + -26c
Remove the zero:
-26c = 88 + 26c + -26c

Combine like terms: 26c + -26c = 0
-26c = 88 + 0
-26c = 88

Divide each side by '-26'.
c = -3.384615385

Simplifying
c = -3.384615385

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