A(-a)+2a-4=8a-24-a2

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Solution for A(-a)+2a-4=8a-24-a2 equation:



(-A)+2A-4=8A-24-A2
We move all terms to the left:
(-A)+2A-4-(8A-24-A2)=0
We add all the numbers together, and all the variables
-(+8A-1A^2-24)+(-1A)+2A-4=0
We add all the numbers together, and all the variables
-(+8A-1A^2-24)+2A+(-1A)-4=0
We get rid of parentheses
1A^2-8A+2A-1A+24-4=0
We add all the numbers together, and all the variables
A^2-7A+20=0
a = 1; b = -7; c = +20;
Δ = b2-4ac
Δ = -72-4·1·20
Δ = -31
Delta is less than zero, so there is no solution for the equation

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