A(10)=-3+(n-1)(4)

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Solution for A(10)=-3+(n-1)(4) equation: 



(10)=-3+(A-1)(4)

We move all terms to the left:

(10)-(-3+(A-1)(4))=0



We calculate terms in parentheses: -(-3+(A-1)4), so:

-3+(A-1)4

determiningTheFunctionDomain
(A-1)4-3

We multiply parentheses

4A-4-3

We add all the numbers together, and all the variables

4A-7

Back to the equation:

-(4A-7)



We get rid of parentheses

-4A+7+10=0

We add all the numbers together, and all the variables

-4A+17=0

We move all terms containing A to the left, all other terms to the right

-4A=-17

A=-17/-4

A=4+1/4

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